const n=10; var min,i: integer; a: array[1..n] of integer; begin randomize; min:=11; for i:=1 to n do begin a[i]:=random(1,10); write (a[i],' '); // для наглядности. можно удалить if (i mod 2 =1) and (a[i]<min) then min:=a[i]; end; writeln; writeln ('min = ',min) end.
Пример: 5 4 7 8 6 2 10 4 9 9 min = 5
2 задача:
const n=10; var max,count,i: integer; a: array[1..n] of integer; begin randomize; max:=0; count:=0; for i:=1 to n do begin a[i]:=random(1,10); write (a[i],' '); // для наглядности. можно удалить if a[i]>max then max:=a[i]; end; for i:=1 to n do if max=a[i] then count:=count+1; writeln; writeln ('max = ',max); writeln ('count = ',count); end.
Вот в двоичной системе: 110010001100110111010100110011101101000011001100110000001101001011001000110010101100000000100000100101110010000011011101110100101100111000100000110011011100000011010011110010101100000000100000110011100010000011010001110011111100111011010001110011101100000111000000110101010010000011001111110011101100101111010011110101111100010111001101110010001101111100101100001000001100110111000000110010101100111011001111110010111100010111001101110010001101111100101100001000001100111011000001110100001100000011000001110011101101001011001010110010000010110000100000110011111100010111010000110001011100010011000000110101111100100000100000110010000010000011001111110100001100010111000100110100011101001011000000110000101100101111000101110011011100100011011111001000001100100011001101110101001100111011010000110011001100000011010110110010001100100000101110
const n=10;
var
min,i: integer;
a: array[1..n] of integer;
begin
randomize;
min:=11;
for i:=1 to n do begin
a[i]:=random(1,10);
write (a[i],' '); // для наглядности. можно удалить
if (i mod 2 =1) and (a[i]<min)
then min:=a[i];
end;
writeln;
writeln ('min = ',min)
end.
Пример:
5 4 7 8 6 2 10 4 9 9
min = 5
2 задача:
const n=10;
var
max,count,i: integer;
a: array[1..n] of integer;
begin
randomize;
max:=0;
count:=0;
for i:=1 to n do begin
a[i]:=random(1,10);
write (a[i],' '); // для наглядности. можно удалить
if a[i]>max
then max:=a[i];
end;
for i:=1 to n do
if max=a[i] then count:=count+1;
writeln;
writeln ('max = ',max);
writeln ('count = ',count);
end.
Пример:
8 5 3 2 2 10 10 9 3 10
max = 10
count = 3
110010001100110111010100110011101101000011001100110000001101001011001000110010101100000000100000100101110010000011011101110100101100111000100000110011011100000011010011110010101100000000100000110011100010000011010001110011111100111011010001110011101100000111000000110101010010000011001111110011101100101111010011110101111100010111001101110010001101111100101100001000001100110111000000110010101100111011001111110010111100010111001101110010001101111100101100001000001100111011000001110100001100000011000001110011101101001011001010110010000010110000100000110011111100010111010000110001011100010011000000110101111100100000100000110010000010000011001111110100001100010111000100110100011101001011000000110000101100101111000101110011011100100011011111001000001100100011001101110101001100111011010000110011001100000011010110110010001100100000101110