5x - 3y + 4z = 6 (1)
2x - y - z = 0 (2)
x - 2y + z = 0 (3)
(2) + ( 3)
2x - y - z + x - 2y + z = 0
3x - 3y = 0
x = y
во второе
2x - x - z = 0
x = z
получили
x = y = z
в первое
5x - 3x + 4x = 6
6x = 6
x = 1
ответ (1,1,1)
5x - 3y + 4z = 6 (1)
2x - y - z = 0 (2)
x - 2y + z = 0 (3)
(2) + ( 3)
2x - y - z + x - 2y + z = 0
3x - 3y = 0
x = y
во второе
2x - x - z = 0
x = z
получили
x = y = z
в первое
5x - 3x + 4x = 6
6x = 6
x = 1
ответ (1,1,1)