дано
m(ppaNaCL) = 292.5 g
W(NaCL) = 10%
m(ppa AgNO3) = 136 g
W(AgNO3) = 25%
m(AgCL) - ?
NaCL+AgNO3-->AgCL+NaNO3
m(NaCL) = m(ppa NaCL) * W(NaCL) / 100% = 292.5 *10 / 100 = 29.25 g
m(AgNO3) = m(ppa AgNO3) * W(AgNO3) / 100% = 136 * 25 / 100 = 34 g
M(NaCL) = 58.5 g/mol
n(NaCL) = m(NaCL) / M(NaCL) = 29.25 / 58.5 = 0.5 mol
M(AgNO3) = 170 g/mol
n(AgNO3) = m(AgNO3) / M(AgNO3) = 34 / 170 = 0.2 mol
n(NaCL) > n(AgNO3)
n(AgNO3) = n(AgCL) = 0.2 mol
M(AgCL) = 143,5 g/mol
m(AgCL) = n(AgCL) * M(AgCL) = 0.2*143.5 = 28.7 g
ответ 28.7 гр
Объяснение:
дано
m(ppaNaCL) = 292.5 g
W(NaCL) = 10%
m(ppa AgNO3) = 136 g
W(AgNO3) = 25%
m(AgCL) - ?
NaCL+AgNO3-->AgCL+NaNO3
m(NaCL) = m(ppa NaCL) * W(NaCL) / 100% = 292.5 *10 / 100 = 29.25 g
m(AgNO3) = m(ppa AgNO3) * W(AgNO3) / 100% = 136 * 25 / 100 = 34 g
M(NaCL) = 58.5 g/mol
n(NaCL) = m(NaCL) / M(NaCL) = 29.25 / 58.5 = 0.5 mol
M(AgNO3) = 170 g/mol
n(AgNO3) = m(AgNO3) / M(AgNO3) = 34 / 170 = 0.2 mol
n(NaCL) > n(AgNO3)
n(AgNO3) = n(AgCL) = 0.2 mol
M(AgCL) = 143,5 g/mol
m(AgCL) = n(AgCL) * M(AgCL) = 0.2*143.5 = 28.7 g
ответ 28.7 гр
Объяснение:
12. 2O(-2)-2e=O2 2 5 восстановитель
Mn(+7)+5e=Mn(+2) 5 2 окислитель
5H2O2+2K2MnO4+44H2SO4=5O2+2MnSO4+2K2SO4+4H2O
13. K2CO3+2HNO3=2KNO3+H2O+CO2
2H(+)+CO3(2-)=H2O+CO2
14.
540*0.6 x mol x L
6HCl + 2Al = 2 AlCl3 + 3H2
54g 2 mol 3*22.4 L
x mol=324*2/54=12 mol (AlCl3)
x L=324*3*22.4/54=403.2 L (H2)
15.
300*0.3=90g
150*0.25=37.5g
mrastvora2=300+150=450g
msoli2=90+37.5=127.5g
w2=127.5/450=0.283 или 28.3%