m(KCl) = n*M = 3.5*74.5 = 260.75 г
m(раствора) = m(H2O) + m(KCl) = 200 + 260.75 = 460.75 г
ω(NaCl) = m(KCl)*100/m(раствора) = 260.75*100/460.75 ≈ 56.6 %
m(KCl) = n*M = 3.5*74.5 = 260.75 г
m(раствора) = m(H2O) + m(KCl) = 200 + 260.75 = 460.75 г
ω(NaCl) = m(KCl)*100/m(раствора) = 260.75*100/460.75 ≈ 56.6 %