дано
m(S) = 40 g
m(Al2S3)-?
2Al+3S-->Al2S3
M(S) = 32 g/mol
n(S) = m/M = 40 / 32 = 1.25 mol
3n(S) =n(Al2S3)
n(Al2S3) = 1.25 / 3 = 0.42 mol
M(AL2S3) = 150 g/mol
m(Al2S3) = n*M = 0.42 * 150 = 63 g
ответ 63 г
Объяснение:
дано
m(S) = 40 g
m(Al2S3)-?
2Al+3S-->Al2S3
M(S) = 32 g/mol
n(S) = m/M = 40 / 32 = 1.25 mol
3n(S) =n(Al2S3)
n(Al2S3) = 1.25 / 3 = 0.42 mol
M(AL2S3) = 150 g/mol
m(Al2S3) = n*M = 0.42 * 150 = 63 g
ответ 63 г
Объяснение: