Beo+=beso4; beso4+=becl2; becl2+=be; be+=na2[be(oh)4]; - вопрос №44222421946218 от AlexeySafronov 11.10.2021 04:23

Question

Химия: Beo+=beso4; beso4+=becl2; becl2+=be; be+=na2[be(oh)4]; beo+=na2[be(oh)4]; beso4+=be(no3)2; na2[be(oh)4]+=be(no3)2;

AlexeySafronov · Answer

BeO+H2SO4=BeSO4+H2OBeSO4+2HCl=BeCl2+ H2SO4BeCl2+H2=Be+ 2HCl(газ) 2Be+4NaOH=2Na2[Be(OH)4]; BeSO4+2HNO3=Be(NO3)2 + H2SO4Na2[Be(OH)4]+4HNO3=Be(NO3)2 + 2NaNO3+4H2O...