Вычислить определенный интеграл методами прямоугольников и трапеций. f(x)=√27-x^3,
a=-7, b=3.

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перенесем оба числа в левую стронуи приравняем 0, т.к. это нам даст определение области значений между этими числами

35х^4-6х^8=0

выделим х^4

х^4(35-6х^4)=0

выражение равно0 только когда хотя бы один из множителей равен 0

либо х^4=0

х=0

либо 35-6х^4=0

35=6х^4

х^4=35/6

расставим знаки +/- на графике. если значение принимает положительное зачение, то 35х^4>6х^8, иначе наоборот

ответ

35х^4<6х^8 при

35х^4=6х^8 при

35х^4>6х^8 при

но меньше 0

35х^4=6х^8 при х=0

35х^4>6х^8 при

х>0 но меньше

35х^4=6х^8 при

35х^4<6х^8 при