™-в квадрате *-в кубе (5m+4n)(4n-5m)+25m™ 12n+(2n-3)™ - вопрос №544525122378183479 от Arina456895 29.11.2020 01:13

Question

Алгебра: ™-в квадрате *-в кубе (5m+4n)(4n-5m)+25m™ 12n+(2n-3)™ (7a-8b)™-(4a-5b)(3a+2b) (y-3z)(y™+3yz+9z™)-y*+26z*

Arina456895 · Answer

(5m+4n)(4n-5m)+25m™= 16n™-25m™+25m™=16n™

12n+(2n-3)™ =12n+4n™-12n-9=4n™-9

(7a-8b)™-(4a-5b)(3a+2b) =49a™-112ab+64b™-12a™-8ab+15ab+10b™=37a™-105ab+74b™

(y-3z)(y™+3yz+9z™)-y*+26z*=y*-27z*-y*+26z*=z*