ОДЗ:
2x(x-1)≠0
{2x ≠ 0 ⇒ x ≠ 0
{x-1≠0 ⇒ x ≠ 1
-3x² + 3x + 2x + 2x - 2 = 0
-3x² + 7x - 2 = 0
3x² - 7x + 2 = 0
D=b²-4ac=49 - 4 * 3 * 2 = 25
x(1) = (-b-√D)/2a = (7 - 5)/6 = 1/3
x(2) = (-b+√D)/2a = (7 + 5)/6 = 2
ответ: 1/3 и 2
ОДЗ:
2x(x-1)≠0
{2x ≠ 0 ⇒ x ≠ 0
{x-1≠0 ⇒ x ≠ 1
-3x² + 3x + 2x + 2x - 2 = 0
-3x² + 7x - 2 = 0
3x² - 7x + 2 = 0
D=b²-4ac=49 - 4 * 3 * 2 = 25
x(1) = (-b-√D)/2a = (7 - 5)/6 = 1/3
x(2) = (-b+√D)/2a = (7 + 5)/6 = 2
ответ: 1/3 и 2