x2 - 0.5x - 5 <0D = b2 - 4acD = 0.25 + 20 = 20.25 = (√20.25)
x1,2 = -b ± √Dx1 = 0.5 + √20.25/2x2 = 0.5 - √20.25/2(x - 0.5 + √20.25/2)(x+ 0.5 - √20.25/2)<0
x2 - 0.5x - 5 <0
D = b2 - 4ac
D = 0.25 + 20 = 20.25 = (√20.25)
x1,2 = -b ± √D
x1 = 0.5 + √20.25/2
x2 = 0.5 - √20.25/2
(x - 0.5 + √20.25/2)(x+ 0.5 - √20.25/2)<0