1)sinx=a
3a²-4a+1=0
D=16-12=4
a1=(4-2)/6=1/3⇒sinx=1/3⇒x=(-1)^n *arcsin1/3+πn
a2=(4+2)/6=1⇒sinx=1⇒x=π/2+2πn
2)tg(3x+π/3)≥-√3
-π/3+πn≤3x+π/3<π/2+πn
-π/3-π/3+πn≤3x<π/2-π/3+πn
-2π/3+πn≤3x<π/6+πn
-2π/9+πn≤x<π/18+πn
x∈[-2π/9+πn;π/18+πn)
Пошаговое объяснение:
1)sinx=a
3a²-4a+1=0
D=16-12=4
a1=(4-2)/6=1/3⇒sinx=1/3⇒x=(-1)^n *arcsin1/3+πn
a2=(4+2)/6=1⇒sinx=1⇒x=π/2+2πn
2)tg(3x+π/3)≥-√3
-π/3+πn≤3x+π/3<π/2+πn
-π/3-π/3+πn≤3x<π/2-π/3+πn
-2π/3+πn≤3x<π/6+πn
-2π/9+πn≤x<π/18+πn
x∈[-2π/9+πn;π/18+πn)
Пошаговое объяснение: