Найдите значение 1)12/7: (6/7-3/4) 2)5/6+5/2*2/3 - вопрос №112767342565223316715193821 от olgaluppo 13.05.2020 14:59

Question

Математика: Найдите значение 1)12/7: (6/7-3/4) 2)5/6+5/2*2/3 3)(1целая 6/7-1,6): 1/70 4)(1/13-11/4)*26 5)(5/12-3/20)*45/2 6)(13/3-2,8)*9/2 7)30/6*0,5*(-10/3)

olgaluppo · Answer

12/7:(6/7-3/4)=12/7:(24/28-21/28)=12/7:3/28=12/7*28/3=4*4=16

5/6+5/2*2/3=5/6+5/3=5/6+10/6=15/6=2 3/6=2 1/2=2,5

(1 6/7-1,6):1/70=(1 6/7-1 6/10):1/70=(1 60/70-1 42/70):1/70=18/70:1/70=18/70*70/1=18

4)
(1/13-11/4)*26=1/13*26-11/4*26=2-143/4=2-35 3/4= - 33 3/4 ???

5)
(5/12-3/20)*45/2=(25/60-9/60)*45/2=16/60*45/2=(8*3)/4=24/4=6

(13/3-2,8)*9/2=13/3*9/2-2 4/5*9/2=39/2-63/5=195/10-126/10=19,5-12,6=6,9

30/6*0,5*(- 10/3)= - 30/6*5/10*10/3= - (5*5)/3= - 25/3= - 8 1/3