12 (cos x - cos *2 x/2 - sin *2 x/2) *2= 10 - 13 - вопрос №122222210133326744 от cat0708200416 28.10.2020 21:43

Question

Математика: 12 (cos x - cos *2 x/2 - sin *2 x/2) *2= 10 - 13 cos x​

cat0708200416 · Answer

12(Сosx -Cos²x/2 - Sin²x/2)² = 10 - 13Cosx

12(Cosx -(Cos²x/2 +Sin²x/2))² = 10 - 13Cosx

12(Cosx -1)² = 10 -13Cosx

12(Cos²x -2Cosx +1) = 10 -13Cosx

12Cos²x -24Cosx +12 - 10 +13Cosx = 0

12Cos²x -11Cosx +2 = 0

cosx = t

12t² -11t +2 = 0

D = 121 - 96 = 25

t₁ = 16/24= 2/3 t₂ = 1/4

Сosx = 2/3 Cosx = 1/4

x = +- arcCos2/3 + 2πk , k ∈Z x = =-arcCos1/4 + 2πn , n ∈Z

12 (cos x - cos *2 x/2 - sin *2 x/2) *2= 10 - 13 cos x​