My dream room. Wow, let's start with the interior I would like my room to have delicate pastel ocher wallpapers, on which I would hang posters of my favorite bands. My room must have a balcony with a table and two chairs. It will be decorated with different flowers and in the morning I will have a cup of coffee there. There will be a large round bed in my room, there will be a work table on the side, a dressing table next to it, a small table. Opposite the tables will be a wardrobe, vast and full of different and interesting outfits. There will be many plants in my room, and I will stretch a bright yellow garland across the ceiling. This is the room of my dreams
Дано: Решение: V(NH₃) = 8.4 л 2NH₃ + H₂SO₄ = (NH₄)₂SO₄ m(p)(H₂SO₄) = 100 г 1) Найдем массу серной кислоты: ω(H₂SO₄) = 24.5% m(H₂SO₄) = 100 × 0.245 = 24.5 г Найти: 2) Найдем количество моль аммиака: n((NH₄)₂SO₄)= ? n(NH₃) = V/Vm = 8.4/34 = 0.25 моль ИЛИ 3) Найдем количество моль серной кислоты: n(NH₃) = ? n(H₂SO₄) = m/M = 24.5/98 = 0.25 моль n(H₂SO₄) Извини, дальше я уже не знаю. Кислота и газ с одинаковым количеством образовали одну единственную соль. Возможно дальнейшее решение а может уже дан ответ, что у них всех по 0.25 моль и, возможно, у соли столько же.
My dream room. Wow, let's start with the interior I would like my room to have delicate pastel ocher wallpapers, on which I would hang posters of my favorite bands. My room must have a balcony with a table and two chairs. It will be decorated with different flowers and in the morning I will have a cup of coffee there. There will be a large round bed in my room, there will be a work table on the side, a dressing table next to it, a small table. Opposite the tables will be a wardrobe, vast and full of different and interesting outfits. There will be many plants in my room, and I will stretch a bright yellow garland across the ceiling. This is the room of my dreams
Объяснение:
V(NH₃) = 8.4 л 2NH₃ + H₂SO₄ = (NH₄)₂SO₄
m(p)(H₂SO₄) = 100 г 1) Найдем массу серной кислоты:
ω(H₂SO₄) = 24.5% m(H₂SO₄) = 100 × 0.245 = 24.5 г
Найти: 2) Найдем количество моль аммиака:
n((NH₄)₂SO₄)= ? n(NH₃) = V/Vm = 8.4/34 = 0.25 моль
ИЛИ 3) Найдем количество моль серной кислоты:
n(NH₃) = ? n(H₂SO₄) = m/M = 24.5/98 = 0.25 моль
n(H₂SO₄) Извини, дальше я уже не знаю. Кислота и газ с одинаковым количеством образовали одну единственную соль. Возможно дальнейшее
решение а может уже дан ответ, что у них всех
по 0.25 моль и, возможно, у соли столько же.