Mr (Al4C3) = 27 × 4 + 12 × 3 = 144 г/моль
ω (Al) = 27 × 4 / 144 × 100% = 108 / 144 × 100% = 0,75 × 100% = 75%
ω (С) = 12 × 3 / 144 × 100 % = 36 / 144 × 100% = 0,25 × 100 % = 25 %
Mr (Al4C3) = 27 × 4 + 12 × 3 = 144 г/моль
ω (Al) = 27 × 4 / 144 × 100% = 108 / 144 × 100% = 0,75 × 100% = 75%
ω (С) = 12 × 3 / 144 × 100 % = 36 / 144 × 100% = 0,25 × 100 % = 25 %