дано
W(C) = 92.3 % = 0.923
M(CxHy) = 78 g/mol
CxHy-?
W(H) = 1-0.923 = 0.077
CxHy / 78 = 0.923 / 12 : 0.077 / 1
CxHy = 6 : 6
C6H6
ответ БЕНЗОЛ
дано
W(C) = 92.3 % = 0.923
M(CxHy) = 78 g/mol
CxHy-?
W(H) = 1-0.923 = 0.077
CxHy / 78 = 0.923 / 12 : 0.077 / 1
CxHy = 6 : 6
C6H6
ответ БЕНЗОЛ