Розв'язати задачі (фото)

1.D за H2(CxHy) = 35

W(C) = 85.7%

W(H) = 14.3%

CxHy - ?

M(CxHy) = 35*2 = 70 g / mol

Ar(C) = 0.857 * 70 = 60.

n(C) = 60 / 12 = 5.

Ar(H) = 70-60 = 10

n(H) = 10 / 1 = 10.

C5H10

2. W(C) = 40%

W(H) = 6.66%

W(O) = 53.34%

CxHyOz - ?

x:y:z = 40 / 12 : 6.66 / 1 : 53.34 / 16 = 3.33 : 6.66 : 3.33 | / 3.33 = 1:2:1

CH2O

3.D за H2 (CxHy) = 42.

W(C) = 85.71%

W(H) = 14.29%

M(CxHy) = 42*2 = 84 g / mol

Ar(C) = 0.8571 * 84 = 72.

n(C) = 72/12 = 6.

Ar(H) = 84 - 72 = 12.

n(H) = 12 / 1 = 12.

C6H12