M(j)= 2.5 * 29 ≈ 72 г/моль
CO2 ==> C
0.05/1 = x/12
x = 0.6 г
H2O ==> 2H
1.08/18 = y/2
y = 0.12
0.12 + 0.6 = 0.72 ==> CxHy
12x = 0.6
x = 0.05
*100
x = 5
y = 12
C5H12 - пентан
M(j)= 2.5 * 29 ≈ 72 г/моль
CO2 ==> C
0.05/1 = x/12
x = 0.6 г
H2O ==> 2H
1.08/18 = y/2
y = 0.12
0.12 + 0.6 = 0.72 ==> CxHy
12x = 0.6
y = 0.12
x = 0.05
y = 0.12
*100
x = 5
y = 12
C5H12 - пентан