m(NaOH)=20*2=40; n(NaOH)=1;
NaOH= Na(+) + (OH-)
1 1 1моль
[H+]*[OH-]=10^ -14
[H+]=10^ -14 : [OH-]
[H+]=10^ -14 : 1=10^ -14
pH= -lg10^ -14=14.
m(NaOH)=20*2=40; n(NaOH)=1;
NaOH= Na(+) + (OH-)
1 1 1моль
[H+]*[OH-]=10^ -14
[H+]=10^ -14 : [OH-]
[H+]=10^ -14 : 1=10^ -14
pH= -lg10^ -14=14.