5.12
Объяснение:
NH4Cl + H2O = HCl + NH3 + H2O;
[H+] = ( (Kw*c(NH4Cl) /Kb)^0.5 = ( (10^-14 *0.1) / (1.8 *10^-5))^0.5 = 7.46 * 10^-6 ;
pH = - log(7.46*10^-6) = 5.12;
5.12
Объяснение:
NH4Cl + H2O = HCl + NH3 + H2O;
[H+] = ( (Kw*c(NH4Cl) /Kb)^0.5 = ( (10^-14 *0.1) / (1.8 *10^-5))^0.5 = 7.46 * 10^-6 ;
pH = - log(7.46*10^-6) = 5.12;