CO2 ==> C
1.79/22.4 = x/12
x = 0.96 г
H2O ==> 2H
1.8/18 = y/2
y = 0.2
12x = 0.96
x = 0.08
x = 4
y = 10
C4H10 — бутан
CO2 ==> C
1.79/22.4 = x/12
x = 0.96 г
H2O ==> 2H
1.8/18 = y/2
y = 0.2
12x = 0.96
y = 0.2
x = 0.08
y = 0.2
x = 4
y = 10
C4H10 — бутан