M (KMnO4) = 39 + 55 + 64 = 158
w(O) = (64/158)* 100%=40,5%
M(KClO3) = 39 + 35,5 + 48 = 122,5
w(O) = (48/122,5)* 100% = 39,2%
M(HgO) = 201 + 16 = 217
w(O) = (16/217)* 100% = 7,37%
M (KMnO4) = 39 + 55 + 64 = 158
w(O) = (64/158)* 100%=40,5%
M(KClO3) = 39 + 35,5 + 48 = 122,5
w(O) = (48/122,5)* 100% = 39,2%
M(HgO) = 201 + 16 = 217
w(O) = (16/217)* 100% = 7,37%