0,056 x
Zn+2HCl=ZnCl2+ H2
1. 1
n(Zn)= 3,65÷65=0,056
n(H2)=0,056
m(H2)=0,056×2=0.112г
V(H2)=0.056×22,4=1,254дм3
0,056 x
Zn+2HCl=ZnCl2+ H2
1. 1
n(Zn)= 3,65÷65=0,056
n(H2)=0,056
m(H2)=0,056×2=0.112г
V(H2)=0.056×22,4=1,254дм3