4Li + O2 = 2Li2O
V(O2) = 89.6 * 0.21 = 18.816
n= 18.816/22.4 = 0.84
n(Li2O)=2*n(O2) = 0.84 *2 = 1.68
m(Li2O) = 30 * 1.68 = 50.4
4Li + O2 = 2Li2O
V(O2) = 89.6 * 0.21 = 18.816
n= 18.816/22.4 = 0.84
n(Li2O)=2*n(O2) = 0.84 *2 = 1.68
m(Li2O) = 30 * 1.68 = 50.4