Найдите массовую долю элементов в веществах mgo - вопрос №228459701 от adamabiev 08.11.2021 23:28

Question

Химия: Найдите массовую долю элементов в веществах mgo , n2o , no , n2o5 , naoh , c6h12o6 , cu(no3)2

adamabiev · Answer

1) M(MgO) = 40W(Mg) = 24/40 = 0,6%W(O) = 16/40 = 0,4%2) M(N2O) = 44W(N) = 14/44 = 0,31%W(O) = 16/44 = 0,36%3) M(NO) = 30W(N) = 14/30 = 0,46%W(O) = 16/30 = 0,53%4) M(N2O5) = 108W(N0 = 14/108 = 0,12%W(O) = 16/108 = 0.14%5) M(NaOH) = 40W(Na) = 23/40 = 0.5%W(O) = 16/40 = 0.4%W(H) = 1/40 = 0.025%6) M(C6H12O6) = 180W(C) = 12/180 = 0.06%W(H) = 1/180 = 0.005%W(O) = 16/180 = 0.08%7) M(Cu(NO3)2) = 188W(Cu) = 64/188 = 0.34%W(N) = 14/188 = 0.07%W(O) = 16/188 = 0.08%...