Ba(OH)2
w(x)=m(x)/m(р-ра)
w(Ba)=137/171=0,8011*100%=80,1%
w(O)=16*2/171=0,1871*100%=18,7%
w(H)=2/171=0,0117*100*=1,2%
Ba(OH)2
w(x)=m(x)/m(р-ра)
w(Ba)=137/171=0,8011*100%=80,1%
w(O)=16*2/171=0,1871*100%=18,7%
w(H)=2/171=0,0117*100*=1,2%