Условие в Паскале может быть простым, то есть состоять из одного простого высказывания (например у>0), а может быть сложным, то есть состоять из нескольких простых высказываний, соединенных между собой логическими связками "и", "или", "не" (проходили в начале этого учебного года). Например: сложное высказывание (х>=2) and(x 10) or (t>10)будет истинным, если хотя бы в одной скобке получим истину. То есть ИЛИ s>10 ИЛИ t>10

Объяснение:

1. List the main components of media.

Digital format, interactivity and multimedia

2. Give an example of a nonlinear and comment on multimedia.

For example, Skyrim will have; audio, video, animation, text, interactivity and image multimedia inside of it. Skype is also a non-linear multimedia as it allows for user input and has interactivity. Skype consists of; video, audio, interactivity, image and text multimedia.

3. Describe the advantages and disadvantages of vector graphics.

Vector images usually require less disk space as compared to bitmap. They are formed mostly by simple gradients or flat colors since they don't require too much disk space.  They don't lose quality when you scale them.  

4. For what purpose uses interlaced scanning and why Currently?

The purpose of using interlaced scanning is to transmit a full frame quickly to reduce flicker.

5. What is the nature of the structural approach to design IP?

About Structural Approach It is based on the assumptions that language can be best learnt through a scientific selection and grading of the structures or patterns of sentences and vocabulary.

#include <iostream>

#define N 2

int main()

{

int i,j;

int A[N], B[N], C[N];

setlocale(LC_ALL, "Russian");

for (i = 0; i < N; i++)

{

 std::cout << "Введите a" << i << ": ";

 std::cin >> A[i];

 std::cout << "Введите b" << i << ": ";

 std::cin >> B[i];

 std::cout << "Введите c" << i << ": ";

 std::cin >> C[i];

}

for (i=0;i<N;i++)

 for (j = i+1; j < N; j++)

 {

  if ((A[i]==A[j])&&(B[i] == B[j])&&(C[i] == C[j]))

   std::cout << "Прямые " << i << "и " << j << " совпадают" << std::endl;

  else if (-A[i] / B[i] == -A[j] / B[j])

   std::cout << "Прямые " << i << " и " << j << " параллельны" << std::endl;

 }

return 0;

}