Упростите логические формулы: 1) (A & B & C) v (A & B & C) v (A & B);

2) (A & B A & B & C vB & C v C) & (C v A & C v A & B & C).

Так как язык не указан, приведу пример на SWI-Prolog.

Код:

read_int(Int) :- read(Int), integer(Int).split_int_by_numbers(0, []) :- !.split_int_by_numbers(N, [Number|Ints]) :- Number is mod(N, 10), RestN is div(N, 10), split_int_by_numbers(RestN, Ints).test_to_div(_, []).test_to_div(N, [Number|Ints]) :- mod(N, Number) =:= 0, test_to_div(N, Ints). test(Int) :- split_int_by_numbers(Int, Numbers), test_to_div(Int, Numbers), write(Int), write(" - Yes!"), nl.test(Int) :- write(Int), write(" - No!"), nl.?- read_int(Int), test(Int).

Буду по порядку добавлять.

1)

uses crt;
var n,s,i:integer;
begin
clrscr;
write('n=');
readln(n);
s:=0;
for i:=1 to n do
s:=s+sqr(i);
write('s=',s);
end.

2)

uses crt;
var a:array [1..100] of real;
n,i,p,o,l:integer;
begin
clrscr;
write('n=');
readln(n);
write('a[n]:');
for i:=1 to n do
begin
readln(a[n]);
if a[n]>0 then p:=p+1;
if a[n]<0 then o:=o+1;
if a[n]=0 then l:=l+1;
end;
writeln(l,p,o);
end.

3)

uses crt;
var a:array [1..100] of real; i,n:integer;
begin
clrscr;
write('n=');
readln(n);
write('a[n]:');
for i:=1 to n do
read(a[i]);
for i:=1 to n do
if (a[i]=0) then writeln('YES')
else writeln('NO');
end.