Пусть общая хорда AB , O₁ и O₂ центры окружностей ;O₁A=O₂A =r ,O₁O₂ =r. --- O₁O₂ ⊥ AB. ΔO₁A O₂ (также ΔO₁BO₂) равносторонние со стороной r. AB= 2*(r√3)/2)⇒r =(AB√3)/3 .
Пусть AB и CD взаимно перпендикулярные хорды (AB ⊥ CD) , P_точка пересечения этих хорд ( P=[AB] ⋂[CD] ) b AP= DP =10 ; BP =CP =16 см.
R - ? Например , из ΔACD: AC/sin∠ADC =2R ⇒R =AC/2sin∠ADC.
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1. We (1) (miss) the first act of the play because when we (2) (arrive) at the theatre the performance already (3) (start) .
2. At the time of the trial last summer Hinkley (4) (be) in prison for eight months.
3. The staff (5) (pay) weekly but now they receive a monthly salary.
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5. What’s the point in (8) (argue) with people who (9) (hold) very strong opinions?
6. Many of the survivors (10) (work) in the fields when the earthquake (11) (to strike) .
Phil (12) (stand) at the door soaked from head to toe: he (13) (run) in the rain.
8. Jim (14) (leave) on the early flight the next morning so he (15) (make) his excuses and (16) (leave) the party before midnight.
9. It seems to me, Minister, that the Government (17) (break) all its pre-election promises regarding the Health Service, (18) ?
10. It (19) (must + rain) really hard. All the passers-by (20) (be) soaked through.
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O₁O₂ ⊥ AB. ΔO₁A O₂ (также ΔO₁BO₂) равносторонние со стороной r.
AB= 2*(r√3)/2)⇒r =(AB√3)/3 .
Пусть AB и CD взаимно перпендикулярные хорды (AB ⊥ CD) , P_точка пересечения этих хорд ( P=[AB] ⋂[CD] ) b AP= DP =10 ; BP =CP =16 см.
R - ?
Например , из ΔACD: AC/sin∠ADC =2R ⇒R =AC/2sin∠ADC.
ΔAPC =ΔBPD (по катетам ) ⇒AC =DB =√(10² +16²) =2√(5² +8²) =2√89 (см).
ΔAPD равнобедренный прямоугольный треугольник
⇒∠ADP || ∠ADC|| =∠DAP=45° .
Следовательно :
R =AC/2sin∠ADC =AC/2sin45° =(2√89)/(2*1/√2) =√178 (см).