Инфинитив There happens a rumour around that you are getting divorced.
A are
В be
C to be
D been
Jane stepped forward and said, ‘Then let me up your boots.’
A to lace
В laces
C to have laced
D lace
When he reached the window and realized what Kathy meant, his sense of propriety seemed a severe shock.
A receive
В to receive
C receives
D received
It was difficult for Hanna not .
A to be spoilt
В be spoilt
C spoilt
D is spoilt
Louise Nevelson is believed by many critics ... the greatest 20th century sculptor.
a. to be
b. have been
c. has been
d. being
The exceptions are too numerous ... any rule to be formulated.
a. to
b. for
c. since
d. as
The tendency ... liquids to turn into gases is well-known.
a. that
b. if
c. for
d. when
Athletes who compete in the Olympic games ... to be amateurs.
a. are supposed
b. suppose
c. they suppose
d. supposedly
The experimental data are said ... with theoretical expectations.
a. to coincide
b. coincide
с coinciding
d. coincided
Oxygen ... to be the most abundant element.
a. known
b. to know
c. is known
d. knowing
ответ:А (-1, -1, -1), В (-1, 3, -1), С (-1, -1, 2)
AB=\sqrt{\big(x_B-x_A\big)^2+\big(y_B-y_A\big)^2+\big(z_B-z_A\big)^2}==\sqrt{\big(-1-(-1)\big)^2+\big(3-(-1)\big)^2+\big(-1-(-1)\big)^2}==\sqrt{0+4^2+0}=4
CB=\sqrt{\big(x_B-x_C\Big)^2+\big(y_B-y_C\big)^2+\big(z_B-z_C\big)^2}==\sqrt{\big(-1-(-1)\big)^2+\big(3-(-1)\big)^2+\big(-1-2\big)^2}==\sqrt{0+16+9}=5
AC=\sqrt{\big(x_C-x_A\big)^2+\big(y_C-y_A\big)^2+\big(z_C-z_A\big)^2}==\sqrt{\big(-1-(-1)\big)^2+\big(-1-(-1)\big)^2+\big(2-(-1)\big)^2}==\sqrt{0+0+3^2}=3
P_{\Delta ABC}=AB+CB+AC=4+5+3=12boxed{\boldsymbol{P_{\Delta ABC}=12}}
Объяснение:
А(3;4) 3^2+4^2 - 25 =0? 9+16-25=0 верно, значит точка А принадлежит окружности
В(10;3) 10^2 + 3^2-25=0 100+9 -25=0 неверно, значит В не принадлежит окружности
С(-1;3) (-1)^2+3^2-25=0, 1+9-25=0 неверно, С не принадлежит окружности
Д(0;5) 0^2+5^2-25=0, 0+25-25=0 верно Д принадлежит окружности
2) подставим координаты центра и значение радиуса в уравнение окружности
(х - 2)^2 +(y - (-3))^2=2^2, (x - 2)^2 + (y + 3)^2 = 4 - уравнение окружности.
А(2; -3) (2 - 2)^2 + (-3 + 3)^2 = 4, 0+0=4 неверно, значит А не принадлежит этой окружности