R1-10om. r2=15 om,r3=12om,r4=6 om,r5=4om,u2=60в. - вопрос №11021531246542602555148 от AGENT284 23.05.2022 08:25

Question

Физика: R1-10om. r2=15 om,r3=12om,r4=6 om,r5=4om,u2=60в. найти силу тока

AGENT284 · Answer

1/R12 = 1/R1+1/R2 = (R1+R2) / (R1*R2);R12 = (R1*R2) / (R1+R2) = (4*6) / (4+6) = 24/10=2.4 Ом 1/R345 = 1/R3+1/R4+1/R5 = 1/12+1/12+1/6 = (1+1+2)/12 = 4/12R345 = 12/4 =3 Ом R = R12 +R345 = 2.4+3 = 5.4 Ом...