1)h'(x)=(3/x)'=-3/x^2
2)v'(h)=(-1/h+3h)'=1/h^2+3
3)f'(x)=(2/3x+3x^2)'=-2/3x^2+6x
4)f'(x)=(x^3(5x-1)(1-2x))'=3x^2*(5x-1)(1-2x)+(5-20x+2)*x^3=15x^3-30x^4-3x^2+6x^3+5x^3-20x^4+2x^3=28x^3-50x^4-3x^2
1)h'(x)=(3/x)'=-3/x^2
2)v'(h)=(-1/h+3h)'=1/h^2+3
3)f'(x)=(2/3x+3x^2)'=-2/3x^2+6x
4)f'(x)=(x^3(5x-1)(1-2x))'=3x^2*(5x-1)(1-2x)+(5-20x+2)*x^3=15x^3-30x^4-3x^2+6x^3+5x^3-20x^4+2x^3=28x^3-50x^4-3x^2