S(40)= -3340
Объяснение:
a1=14; d= -5
S(40)=?
S(n)=n/2 ×(2a1+ (n-1)×d)
S(40)=40/2 × (2×14+(40-1)×(-5)) =20×(28+39×(-5))=20×(28-195) = -3340
S(40)= -3340
Объяснение:
a1=14; d= -5
S(40)=?
S(n)=n/2 ×(2a1+ (n-1)×d)
S(40)=40/2 × (2×14+(40-1)×(-5)) =20×(28+39×(-5))=20×(28-195) = -3340