f`(x)=x^2-4
x^2-4=0
x1=-2 /e[0,3]
x2=2
f(0)=0
f(3)=9-12=-3
f(2)=8/3-8=-16/3=-5 1/3
maxf(x)=f(0)=0
minf(x)=f(2)=-16/3
f`(x)=x^2-4
x^2-4=0
x1=-2 /e[0,3]
x2=2
f(0)=0
f(3)=9-12=-3
f(2)=8/3-8=-16/3=-5 1/3
maxf(x)=f(0)=0
minf(x)=f(2)=-16/3