В прямоугольник 7×6 см2 вписан круг радиуса 3 см. Какова вероятность

того, что точка, случайным образом поставленная в прямоугольник, окажется

внутри круга? ответ округлите до тысячных.

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Ответ:

fonato

29.07.2020 05:29

125

1. х² + 5х – 14 = 0

а = 1, b = 5, c = -14

D = b² – 4ac = 5² – 4•(–14)•1 = 25 + 56 = 81 = 9²

$x1 = \frac{ - 5 - 9}{2} = \frac{ - 14}{2} = - 7$

$x2 = \frac{ - 5 + 9}{2} = \frac{4}{2} = 2$

2. х² – 14х + 40 = 0

a = 1, b = -14, c = 40

D = (-14)² - 4•40•1 = 196 – 160 = 36 = 6²

$x1 = \frac{14 - 6}{2} = \frac{8}{2} = 4$

$x2 = \frac{14 + 6}{2} = \frac{20}{2} = 10$

3. 3у² - 13у + 4 = 0

a = 3, b = -13, c = 4

D = (-13)² - 4•3•4 = 169 – 48 = 121 = 11²

$y1 = \frac{13 - 11}{3 \times 2} = \frac{2}{6} = \frac{1}{3}$

$y2 = \frac{13 + 11}{6} = \frac{24}{6} = 4$

4. 12m² + m - 6 = 0

a = 12, b = 1, c = -6

D = 1² - 4•12•(-6) = 1 + 288 = 289 = 17²

$m1 = \frac{ - 1 - 17}{12 \times 2} = \frac{ - 18}{24} = \frac{ - 3}{4}$

$m2 = \frac{ - 1 + 17}{24} = \frac{16}{24} = \frac{2}{3}$

5. x² + 6x - 2 = 0

a = 1, b = 6, c = -2

D = 6² – 4•1•(-2) = 36 + 8 = 44 = √44

$x1 = \frac{ - 6 - \sqrt{44} }{2} = -6 - \sqrt{11}$

$x2 = \frac{ - 6 + \sqrt{44} }{2}= -6 + \sqrt{11}$

6. 3x² - 4x - 5 = 0

a = 3, b = -4, c = -5

D = (-4)² – 4•3•(-5) = 16 + 60 = 76 = √76

$x1 = \frac{4 - \sqrt{76} }{6} = \frac{4 - 2 \sqrt{19} }{6} = \frac{4 - \sqrt{19} }{3}$

$x2 = \frac{4 + \sqrt{76} }{6} = \frac{4 + 2 \sqrt{19} }{6} = \frac{4 + \sqrt{19} }{3}$

7. 25x² + 60x + 36 = 0

a = 25, b = 60, c = 36

D = 60² – 4•25•36 = 3600 – 3600 = 0

$x = \frac{ - b}{2a} = \frac{ - 60}{2 \times 25} = \frac{ - 60}{50} = 1.2$

8. x² - 8x + 18 = 0

a = 1, b = -8, c = 18

D = (-8)² – 4•18•1 = 64 - 72 = -8

Нет корней

126

1. (4х + 1)(х - 3) = 12

4х² - 12х + х - 3 = 12

4х² - 11х - 15 = 0

a = 4, b = -11, c = -15

D = (-11)² – 4•4•(-15) = 121 + 240 = 361 = 19

$x1 = \frac{11 - 19}{2 \times 4} = \frac{ - 8}{8} = - 1$

$x2 = \frac{ 11 + 19}{8} = \frac{30}{8} = 3.75$

2. (x + 2)(x - 3) – (2x - 5)(x+3) = x(x-5)

x² - 3x + 2x - 6 – 2x² - 6x + 5x + 15 – x² + 5x = 0

–2x² + 3x + 9 = 0

a = -2, b = 3, c = 9

D = 3² – 4•9•(-2) = 9 + 72 = 81 = 9²

$x1 = \frac{ - 3 - 9}{2 \times ( - 2)} = \frac{ - 11}{ - 4} = 2.75$

$x2 = \frac{ - 3 + 9}{ - 4} = \frac{6}{ - 4} = - 1.5$

3. (6x - 5)² + (3x - 2)(3x + 2) = 36

((6x)² - 2•6x•5 + 5²) + (9x² - 4) = 36

36x² – 60x + 25 + 9x ² – 4 – 36 = 0

$\frac{45x² – 60x – 15 = 0}{15}$

3x² – 4x = 0

x (3x – 4) = 0

x = 0 или 3х – 4 = 0

$\: \: \: \: \: \: \: \: \: \: \: x = \frac{4}{3}$

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Ответ:

Адильхан435

31.03.2023 01:55

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