умоляю! 2*(x+y) – 3*(4 – y) = 5*(x + 3)4x – 2y + 12 - вопрос №23453421211513591454 от Natasha1146 29.05.2020 11:37

Question

Алгебра: умоляю! 2*(x+y) – 3*(4 – y) = 5*(x + 3)4x – 2y + 12 = 11x – 5y + 37*( х – 5 + 2у + 3) = 114х – 13 = у3х – 12у = 13Х + 6у = 512х – у = 145х + 5у = 17​

Natasha1146 · Answer

12х- у = 145х+5у=1712х - у= 14 / *55х+ 5у= 1760х - 5у = 70 / +5х +5у = 17 / +65х = 87х = 87 : 65х = 87/655х + 5у = 175 * 87/65 + 5у = 1787/13 + 5у = 175у = 17 - 87/135у = 221/13 - 87/13 5у = 134/13у = 134/13 : 1/5у = 134/65ПРОВЕРКА:(5 * 87/65) + (5 * 134/65) = 87/13 + 134/13 = 221/13 = 17...

умоляю! 2*(x+y) – 3*(4 – y) = 5*(x + 3)4x – 2y + 12 = 11x – 5y + 37*( х – 5 + 2у + 3) = 114х – 13 = у3х – 12у = 13Х + 6у = 512х – у = 145х + 5у = 17​

умоляю! 2(x+y) – 3(4 – y) = 5(x + 3)
4x – 2y + 12 = 11x – 5y + 3

7( х – 5 + 2у + 3) = 11
4х – 13 = у

3х – 12у = 13
Х + 6у = 5

12х – у = 14
5х + 5у = 17