f(3 – x) = 2x^2 + 3x – 1
f(x)=f(3-3+x)=f(3-(3-x))=2(3-x)^2+3(3-x)-1=2(9-6x+x^2)+9-3x-1=18-12x+2x^2+9-3x-1=2x^2-15x+26
f(x)=2x^2-15x+26
f(3 – x) = 2x^2 + 3x – 1
f(x)=f(3-3+x)=f(3-(3-x))=2(3-x)^2+3(3-x)-1=2(9-6x+x^2)+9-3x-1=18-12x+2x^2+9-3x-1=2x^2-15x+26
f(x)=2x^2-15x+26