Решите уравнения 11√х=1 3√х-7=0 2-5√2х=0 4+5√х=0 - вопрос №1113702520450242208311609 от Lox2222222288 16.06.2021 06:38

Question

Алгебра: Решите уравнения 11√х=1 3√х-7=0 2-5√2х=0 4+5√х=0 √х-2=4 х^2-2=0,89 1/4a^2=1 (х-3)^2=169

Lox2222222288 · Answer

1) 11√х = 1 √х = 1/11x = 1/121x = 0,00832) 3√х - 7 = 03√х = 7√x = 7 / 3x = 49 / 9x = 5,443) 2 - 5√2х = 0-5√2x = -2√2x = 2 / 52x = 4 / 25x = 2 / 25x = 0,084) 4 + 5√х = 05√x = -4√x = -(4 / 5)Решения нет5) √х - 2 = 4√x = 2x = 46) х^2 - 2 = 0,89x^2 - 2 = 89 / 100x^2 = (89 / 100) + 2x^2 = 289 / 100x1 = 17 / 10     x2 = -(17/10)x1 = 1,7           x2 = -1,77) 1/4a^2 = 1a^2 = 4a1 = 2         a2 = -28) (х-3)^2 = 169x - 3 = +-13x1 = 16        x2 = -10...