1) ∫₀¹ (x + 6) dx = x²/2 + 6x∣¹₀ = 1²/2 + 6*1 = 1/2 + 6 = 6.5
ответ: 6.5.
2π
2) ∫ cos (x/6) dx = [u=x/6; du = 1/6dx => dx = 6du] =
π
2π 2π
= 6 ∫ cos u du = 6sin u = 6sin (x/6) | =
π π
= 6sin(π/3) - 6sin(π/6) = 3√3 - 3 = 3(√3 - 1)
ответ: 3(√3 - 1).
1) ∫₀¹ (x + 6) dx = x²/2 + 6x∣¹₀ = 1²/2 + 6*1 = 1/2 + 6 = 6.5
ответ: 6.5.
2π
2) ∫ cos (x/6) dx = [u=x/6; du = 1/6dx => dx = 6du] =
π
2π 2π
= 6 ∫ cos u du = 6sin u = 6sin (x/6) | =
π π
= 6sin(π/3) - 6sin(π/6) = 3√3 - 3 = 3(√3 - 1)
ответ: 3(√3 - 1).