Решить уравнение: 3-4sin^2(3x+п/3)=0 - вопрос №3423307419731 от lemannv 02.02.2023 23:11

Question

Алгебра: Решить уравнение: 3-4sin^2(3x+п/3)=0

lemannv · Answer

3 - 4sin²(3x + π/3) = 03 = 4sin²(3x + π/3)sin²(3x + π/3) = 3/4sin(3x + π/3) = ±√3/21) sin(3x + π/3) = √3/23x + π/3 = (-1)ⁿπ/3 + πn, n ∈ Zx = (-1)ⁿπ/9 - π/9 + πn/3, n ∈ Z2) sin(3x + π/3) = -√3/23x + π/3 = (-1)ⁿ+¹π/3 + πn, n ∈ Zx = (-1)ⁿ+¹π/9 - π/9 + πn/3, n ∈ Z...