(3sin(x)−3)(tg(x)−
3
)=0
x
=
2
π
+πk
3sin(x)−3=0
sin(x)=1
x=
+2πk
tg(x)−
=0
tg(x)=
x=arctg(
)+πk
k∈Z
ответ :x=\frac{\pi}{3} +\pi kx=
(3sin(x)−3)(tg(x)−
3
)=0
x
=
2
π
+πk
3sin(x)−3=0
sin(x)=1
x=
2
π
+2πk
tg(x)−
3
=0
tg(x)=
3
x=arctg(
3
)+πk
x=
3
π
+πk
k∈Z
ответ :x=\frac{\pi}{3} +\pi kx=
3
π
+πk