6) 4) 3) 5) 1)
Объяснение:
-x²-5x+14 < 0
D = b²-4ac = 25-4*(-1)*14 = 81
x₁,₂ = (-b ± √D)/2a = (5 ± √81)/-2 = (5 ± 9)/-2
x₁ = -7
x₂ = 2
x ∈ (-∞; -7) ∪ (2; +∞)
6) 4) 3) 5) 1)
Объяснение:
-x²-5x+14 < 0
D = b²-4ac = 25-4*(-1)*14 = 81
x₁,₂ = (-b ± √D)/2a = (5 ± √81)/-2 = (5 ± 9)/-2
x₁ = -7
x₂ = 2
x ∈ (-∞; -7) ∪ (2; +∞)