Read the text. In each gap there should be a phrase consisting of two words. First match the two halves of the following common collocations and then use the expressions in the following text. ‘Training’ is the latest way of spending the 1) __. Young people with backpacks and whole families may enjoy such holidays. Instead of going to just one place, you travel by train all around Europe. The 2) __ of the trip is 3) __ . Summer travellers can buy so-called ‘holiday passes’ – 4) __ for most European railways for use in June, July and August. If you are 26 or younger, you can pay 30% less the ticket but you must have a valid 5) __ . Remember, there must be your photograph on it!
1)quite
2)student
3)special
4)total
5)summer
6)low
7)tickets
8)months
9)costs
10)card
Система линейных уравнений с двумя неизвестными
x + y = 5
2x - 3y = 1
Система линейных ур-ний с тремя неизвестными
2*x = 2
5*y = 10
x + y + z = 3
Система дробно-рациональных уравнений
x + y = 3
1/x + 1/y = 2/5
Система четырёх уравнений
x1 + 2x2 + 3x3 - 2x4 = 1
2x1 - x2 - 2x3 - 3x4 = 2
3x1 + 2x2 - x3 + 2x4 = -5
2x1 - 3x2 + 2x3 + x4 = 11
Система линейных уравнений с четырьмя неизвестными
2x + 4y + 6z + 8v = 100
3x + 5y + 7z + 9v = 116
3x - 5y + 7z - 9v = -40
-2x + 4y - 6z + 8v = 36
Система трёх нелинейных ур-ний, содержащая квадрат и дробь
2/x = 11
x - 3*z^2 = 0
2/7*x + y - z = -3
Система двух ур-ний, содержащая куб (3-ю степень)
x = y^3
x*y = -5
Система ур-ний c квадратным корнем
x + y - sqrt(x*y) = 5
2*x*y = 3
Система тригонометрических ур-ний
x + y = 5*pi/2
sin(x) + cos(2y) = -1
Система показательных и логарифмических уравнений
y - log(x)/log(3) = 1
x^y = 3^12
Объяснение:
1.
216х² - 6у⁴ = 6 * (36х² - у⁴) = 6*(6х - у²)(6х + у²) (ответ Е),
2.
а)
S = 6а² = 6*(3х - 4)² = 6*(9х² - 24х + 16) = 54х² - 144х + 96,
б)
V = а³ = (3х - 4)³ = 27х³ - 108х² + 144х - 16,
3.
а)
4,3² - 2,58 + 0,3² = 4,3² - 2*4,3*0,3 + 0,3² = (4,3 - 0,3)² = 4² = 16,
б)
(44² - 12²) / (56² - 16²) = (44 - 12)(44 + 12) / (56 - 16)(56 + 16) =
= (32*56) / (40*72) = 28/45,
4.
1 число - х,
2 число - (х-52),
х² - (х-52)² = 208,
х² - х² + 104х - 2704 = 208,
104х = 208 + 2704,
104х = 2912,
х = 28 - 1 число,
х-52 = 28 - 52 = -24 - 2 число