Памагити1) (2,3x - 10) (5,29x2 + 23x + 100) - - вопрос №1231052922310012512167210701040 от LEH9 08.09.2022 00:11

Question

Алгебра: Памагити1) (2,3x - 10) (5,29x2 + 23x + 100) - 125x = 12,167xº;2) (20 + 1,7x) (2,89x2 - 34x + 400) - 400x = 4,913x3;3) 5(x – 6): - 13(2 + x)3 + 32 = -8x²(x + 21);4)-6(4 + x): + 3(5 - x)3 = 1017 - 9x²(3 + x).​

LEH9 · Answer

Объяснение:1) (2,3x-10)(5,29x²+23x+100)-125x=12,167x³12,167x³-1000-125x=12,167x³-125x=1000|:(-125)x=-8ответ: -8.2) 5*(x-6)³-13*(2+x)³+32=-8x²*(x+21)5*(x³-18x²+108x-216)-13*(8+12x+6x²+x³)+32=-8x³-168x²5x³-90x²+540x-1080-104-156x-78x²-13x³+32+8x³+168x²=0384x=1080+104-32384x=1152|:384x=3ответ: 3....

Памагити1) (2,3x - 10) (5,29x2 + 23x + 100) - 125x = 12,167xº;2) (20 + 1,7x) (2,89x2 - 34x + 400) - 400x = 4,913x3;3) 5(x – 6): - 13(2 + x)3 + 32 = -8x²(x + 21);4)-6(4 + x): + 3(5 - x)3 = 1017 - 9x²(3 + x).​

Памагити

1) (2,3x - 10) (5,29x2 + 23x + 100) - 125x = 12,167xº;
2) (20 + 1,7x) (2,89x2 - 34x + 400) - 400x = 4,913x3;
3) 5(x – 6): - 13(2 + x)3 + 32 = -8x²(x + 21);
4)-6(4 + x): + 3(5 - x)3 = 1017 - 9x²(3 + x).