Based on two different cases:
x
=
π
6
,
5
or
3
2
Look below for the explanation of these two cases.
Explanation:
Since,
cos
+
sin
1
we have:
−
So we can replace
in the equation
by
(
)
⇒
or,
0
using the quadratic formula:
b
±
√
4
a
c
for quadratic equation
⋅
8
9
Case I:
for the condition:
≤
to get positive value of
Case II:
to get negative value of
Answer link
Объяснение:
Одночлен Стандартный вид Коэффициент Степень
одночлена одночлена
-3a²b³*a -3a³b³ -3 6
2a²b*b*a 2a³b² 2 5
a²*3xxx 3a²x³ 3 5
5x*7y 35xy 35 2
-5abc*c -5abc² -5 4
-xzxx -x³z -1 4.
Based on two different cases:
x
=
π
6
,
5
π
6
or
3
π
2
Look below for the explanation of these two cases.
Explanation:
Since,
cos
x
+
sin
2
x
=
1
we have:
cos
2
x
=
1
−
sin
2
x
So we can replace
cos
2
x
in the equation
1
+
sin
x
=
2
cos
2
x
by
(
1
−
sin
2
x
)
⇒
2
(
1
−
sin
2
x
)
=
sin
x
+
1
or,
2
−
2
sin
2
x
=
sin
x
+
1
or,
0
=
2
sin
2
x
+
sin
x
+
1
−
2
or,
2
sin
2
x
+
sin
x
−
1
=
0
using the quadratic formula:
x
=
−
b
±
√
b
2
−
4
a
c
2
a
for quadratic equation
a
x
2
+
b
x
+
c
=
0
we have:
sin
x
=
−
1
±
√
1
2
−
4
⋅
2
⋅
(
−
1
)
2
⋅
2
or,
sin
x
=
−
1
±
√
1
+
8
4
or,
sin
x
=
−
1
±
√
9
4
or,
sin
x
=
−
1
±
3
4
or,
sin
x
=
−
1
+
3
4
,
−
1
−
3
4
or,
sin
x
=
1
2
,
−
1
Case I:
sin
x
=
1
2
for the condition:
0
≤
x
≤
2
π
we have:
x
=
π
6
or
5
π
6
to get positive value of
sin
x
Case II:
sin
x
=
−
1
we have:
x
=
3
π
2
to get negative value of
sin
x
Answer link
Объяснение:
Объяснение:
Одночлен Стандартный вид Коэффициент Степень
одночлена одночлена
-3a²b³*a -3a³b³ -3 6
2a²b*b*a 2a³b² 2 5
a²*3xxx 3a²x³ 3 5
5x*7y 35xy 35 2
-5abc*c -5abc² -5 4
-xzxx -x³z -1 4.