R.E.F image
In Δ ABC, B is at right angle.
Given, AB=24cm
BC=7cm
using Pythagoras theorem
AB
2
+BC
=AC
⇒(24)
+(7)
⇒AC=
(24
)+(7)
=
576+49
625
⇒AC=25CM
(i)sin A=
AC
BC
25
7
cos A=
24
(ii)sin C=
cos c=
Объяснение:
R.E.F image
In Δ ABC, B is at right angle.
Given, AB=24cm
BC=7cm
using Pythagoras theorem
AB
2
+BC
2
=AC
2
⇒(24)
2
+(7)
2
=AC
2
⇒AC=
(24
2
)+(7)
2
=
576+49
=
625
⇒AC=25CM
(i)sin A=
AC
BC
=
25
7
cos A=
AC
AB
=
25
24
(ii)sin C=
AC
AB
=
25
24
cos c=
AC
BC
=
25
7
Объяснение: