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2. На фото))
3. Пусть одна сторона треугольника = х, тогда вторая - х+7
Площадь треугольника ищем по формуле: S=первая сторона*вторую сторону, можем записать уравнение:
х*(х+7)=44
х^2+7х=44
х^2+7х-44=0
Получаем квадратное уравнение, решив которое получим 2 корня: х1=-11(не подходит, так как длина стороны не может быть отрицательным числом), х2=4
Значит, первая сторона равна - 4 см, а вторая-4+7=11 (см).
4. По теореме Виета:
-6+х2=-b/2
-6*x2=-6/2
Находим х2 с второго выражения
-6*x2=-6/2
-6*x2=-3
х2=1/2
Теперь ищем b с первого выражения
-6+1/2=-b/2
-11/2=-b/2
-11=-b
b=11
5. Уравнение имеет 1-н корень если дискриминант = 0.
D=16-4*2*a=0. 16-8a=0. 8a=16. a=2
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