-2x+2x^2 +3x-12=-x^2-2x-6x
2x^2+x-12+x^2+2x+6x=0
3x^2+9x-12=0
x^2+3x-4=0
x1+x2= -3
x1*x2= -4
x1= -4
x2= 1
Відповідь:
-2x+2x^2+3x-12=-x^2-2x-6x
D = b^2 - 4ac = 92 - 4·3·(-12) = 81 + 144 = 225
x1 = (-9 - √225)/ (2·3) = (-9 - 15)/6 = -24/6 = -4
x2 = (-9 + √225)/(2·3) = (-9 + 15)/6 = 6/6 = 1
-2x+2x^2 +3x-12=-x^2-2x-6x
2x^2+x-12+x^2+2x+6x=0
3x^2+9x-12=0
x^2+3x-4=0
x1+x2= -3
x1*x2= -4
x1= -4
x2= 1
Відповідь:
-2x+2x^2+3x-12=-x^2-2x-6x
3x^2+9x-12=0
D = b^2 - 4ac = 92 - 4·3·(-12) = 81 + 144 = 225
x1 = (-9 - √225)/ (2·3) = (-9 - 15)/6 = -24/6 = -4
x2 = (-9 + √225)/(2·3) = (-9 + 15)/6 = 6/6 = 1