(4+1)(4^2+1)(4^4+1)(4^8+1)-1/3*4^16 распишите, - вопрос №4142144148113416135824138 от mariyapetrpet 21.02.2023 09:32

Question

Алгебра: (4+1)(4^2+1)(4^4+1)(4^8+1)-1/3*4^16 распишите, . ответ: -1/3

mariyapetrpet · Answer

(4+1)(4^2+1)(4^4+1)(4^8+1) = (4-1)(4+1)(4^2+1)(4^4+1)(4^8+1)/(4-1) = (4^2-1)(4^2+1)(4^4+1)(4^8+1)/3=(4^4-1)(4^4+1)(4^8+1)/3=(4^8-1)(4^8+1)/3=(4^16-1)/3.
(4^16-1)/3-1/3*4^16=4^16 / 3 - 1/3 - 4^16 / 3 = -1/3.