D = b^2 - 4ac = (-5)^2 - 4*3*(-2) = 25 +24 = 49. ✓D = 7.
x = (-b +- ✓D)/2a
x1 = (5 + 7)/2*3 = 12/6 = 2.
x2 = (5 - 7)2*3 = -2/6 = -1/3.
ответ: -1, 6
Объяснение:
3t²-5t-2=0
D=25-4×3×(-2)=25+24=49
t1=(5-7)÷2= -2÷2= -1
t2=(5+7)÷2=12÷2=6;
t1= -1;. t2=6
D = b^2 - 4ac = (-5)^2 - 4*3*(-2) = 25 +24 = 49. ✓D = 7.
x = (-b +- ✓D)/2a
x1 = (5 + 7)/2*3 = 12/6 = 2.
x2 = (5 - 7)2*3 = -2/6 = -1/3.
ответ: -1, 6
Объяснение:
3t²-5t-2=0
D=25-4×3×(-2)=25+24=49
t1=(5-7)÷2= -2÷2= -1
t2=(5+7)÷2=12÷2=6;
t1= -1;. t2=6